The EU elections are different to general elections aren't they?
So my pro-EU vote, in my 70% Tory stronghold, will actually matter?
These ones are local, rather than EU; but EU elections are proportional representation, with the nation being divided into 9 consitituencies getting 5-7 MEPs each (I think that's right). Consequently, tactical voting is utterly pointlesss, so just vote for whom you want to be represented by (or who agrees with your stance on the EU, as it really will be a single-issue vote, with typically low turnout, meaning that each individual vote counts for more).
State of play in the locals from about 2 hours ago (most up to date I can easily find in handy graph format)
https://twitter.com/bbcelection/status/1124262307196997634
ETA: just copy/pasting a post from elsewhere on the EU electoral system (not my original, but a good summary):
"The D'Hondt system aims to assign each seat to the largest number of votes.
For simplicity's sake, lets assume the East Midlands region has 1.000.000 votes. In the example quoted Brexit Party has 300.000 votes, Labour has 200.000, Conservatives 160.000 and Lib-Dems 90.000 (we'll ignore the rest for now). So the first of the 5 seats should obviously go to the Brexit Party. This seat would represent 300.000 votes. Second goes to Labour, and represents 200.000 votes, and third to the Tories, representing 160.000 votes. Now we could give the fourth seat to the Lib-Dems, but it would only represent 90.000 votes. If we give it to the Brexit Party instead, though, it would represent 150.000 votes (half of the votes the Brexit Party got). Similarly with the fifth and final seat, if we give it to Labour it will represent 100.000 seats, which is more than the Lib-Dems got, so to Labour it goes.
Some people criticize the D'Hondt system for under-representing minority parties (which it does), but it has a solid rationale behind it."